Certainly! It is crucial to grasp the general form of a quadratic equation as it serves as the cornerstone for understanding these mathematical expressions. By familiarizing ourselves with this structure, we can readily discern the coefficients ‘a,’ ‘b,’ and ‘c.’ In our particular equation, ‘a’ takes the value of 1, ‘b’ is -11, and ‘c’ is 28.
Quadratic equations are a realm of mathematical problems that can be tackled using various methods. Let’s explore two prominent techniques:
Quadratic Formula
The quadratic formula emerges as a versatile and universally applicable approach to solving quadratic equations. This formula, often called upon, is:
x = (-b ± √(b^2 – 4ac)) / 2a
With this formula, we obtain the roots of the equation, representing the values of ‘x’ that render the equation equal to zero.
x^2-11x+28=0: A Case Study
Intriguingly, we now turn our attention to the specific equation x2-11x+28=0. Our exploration will involve a step-by-step analysis using the quadratic formula.
Step 1: Identifying the Coefficients
To initiate this journey, we must first identify the coefficients. In the equation at hand, ‘a’ is 1, ‘b’ is -11, and ‘c’ is 28.
Step 2: Applying the Quadratic Formula
With the coefficients now in our grasp, we can proceed to apply the quadratic formula. The equation takes shape as follows:
x = (-(-11) ± √((-11)^2 – 4 * 1 * 28)) / (2 * 1)
In the pursuit of a solution, we simplify the equation, leading to:
x = (11 ± √(121 – 112)) / 2
x = (11 ± √9) / 2
Step 3: Finding the Roots
As the equation begins to crystallize, we uncover two potential solutions:
- x = (11 + 3) / 2 = 7
- x = (11 – 3) / 2 = 4
Thus, the roots of the equation x2-11x+28=0 are revealed as x = 7 and x = 4.
Graphical Representation of Quadratic Equations